Mathematics
herri
11

What is the axis of symmetry and vertex for y=3x^2+18x+9?

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(1) Answers
andreinicusors

Vertex: y = 3x² + 18x + 9        y - 9 = 3x² + 18x        y - 9 = 3(x²) + 3(6x)        y - 9 = 3(x² + 6x)  y - 9 + 9 = 3(x² + 6x + 9)             y = 3(x² + 6x + 9)             y = 3(x² + 3x + 3x + 9)             y = 3(x(x) + x(3) + 3(x) + 3(3))             y = 3(x(x + 3) + 3(x + 3))             y = 3(x + 3)(x + 3)             y = 3(x + 3)²             y = 3(x - (-3))²       (h, k) = (-3, 0) Axis of Symmetry: [latex]x = -\frac{b}{2a}[/latex]                               [latex]x = -\frac{18}{2(3)}[/latex]                               [latex]x = -\frac{18}{6}[/latex]                               [latex]x = -3[/latex] The axis of symmetry is -3; the vertex is (-3, 0).

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