Mathematics
KimiLagana939
21

what is the completely factored form of f(x)=6x^3-13x^2-4x+15? a. (x+1)(6x^2-19x+15) b. (x+1)^2(2x-3) c. (x+1)(3x-2)(5x-3) d. (x+1)(2x-3)(3x-5)

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(1) Answers
nikolak

f(x) = 6x³ - 13x² - 4x + 15 f(x) = 6x³ - 19x² + 6x² + 15x - 19x + 15 f(x) = 6x² - 19x² + 15x + 6x² - 19x + 15 f(x) = x(6x²) - x(19x) + x(15) + 1(6x²) - 1(19x) + 1(15) f(x) = x(6x² - 19x + 15) + 1(6x² - 19x + 15) f(x) = (x + 1)(6x² - 19x + 15) f(x) = (x + 1)(6x² - 10x - 9x + 15) f(x) = (x + 1)(2x(3x) - 2x(5) - 3(3x) + 3(5)) f(x) = (x + 1)(2x(3x - 5) - 3(3x - 5)) f(x) = (x + 1)(2x - 3)(3x - 5) The answer is D.

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