What is the slope of the line that passes through the points (4, -6) and (10, 12)?

We know the equation has to be in the form y=mx+c 12--6/10-4 =18/6 =3 (this 3 is our m value) now we know the gradient we can substitute in one of the points y=3x+c 12=(3×10)+c 12=30+c -18=c therefore the equation of line is y=3x-18

the equation for finding the slope of a line is [latex] \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }} [/latex] . Inserting the points, we get [latex] \frac{ -6 - 12 }{ 4 - 10 }} [/latex]  which is 6 / 6 or 1.