lsonger
7

what is the slope of the line through (-4,2) and (5,8)

$Slope = \frac{y_2 - y_2 }{x_2 - x_1} \\ \frac{8-2}{5 - (-4)} = \frac{2}{3} \\\boxed{\frac{2}{3}}$
The two points are in the form are $\sf(x_1,y_1)~ and ~(x_2,y_2)$ The slope formula is $\huge{\sf{slope= \frac{y_2-y_1}{x_2-x_1} }}$ So plugging in our two points we get $\frac{8-2}{5-(-4)} =\frac{6}{5+4} = \frac{6}{9} = \frac{2}{3}$ So the slope is 2/3