# What is the value of work done on an object when a 70-newton force moves it 9.0 meters in the same direction as the force?

(2) Answers

W=F(ΔX)cosθ W=70N(9.0m)cos0° W=630J

We know that: W=Fs W=70N*9m W=630J

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(2) Answers

W=F(ΔX)cosθ W=70N(9.0m)cos0° W=630J

We know that: W=Fs W=70N*9m W=630J

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