What is the volume occupied by 0.106 mol of helium gas at a pressure of 0.99 atm and a temperature of 309 K ?
(1) Answers
0.99 x volume= 0.106 x 0.082 x 309 volume= 2.71 ml
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0.99 x volume= 0.106 x 0.082 x 309 volume= 2.71 ml