Chemistry
Dangela197134
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When 28 g of nitrogen and 6 g of hydrogen react, 34 g of ammonia are produced. if 100 g of nitrogen react with 6 g of hydrogen, how much ammonia will be produced?

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(1) Answers
kearalacy

N2 + 3H2 --> 2NH3 When 100g of N2 , no of moles of N2= 100/(28)=3.57 mol no. of moles of h2 = 6/(2)=3mol Therefore h2 is limiting reagent. no. of moles of ammonia= 3/3*2=2moles mass of ammonia produced= 2 mol * (14+3)= 34g

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