(2) Answers

[latex]y=\log(x^2+x)\\ y'=\frac{1}{(x^2+x)\ln 10}\cdot(2x+1)\\ y=\frac{2x+1}{(x^2+x)\ln 10}[/latex]

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(2) Answers

[latex]y=\log(x^2+x)\\ y'=\frac{1}{(x^2+x)\ln 10}\cdot(2x+1)\\ y=\frac{2x+1}{(x^2+x)\ln 10}[/latex]

Answer is in the attachment below. Please open it up in a new window to see it in full.

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