Matemática
nathanmarques
3

a(8-2i)-(4+3i) b) (6+10i)-(1-3i) c) (5-2i).(1+3i)

+0
(1) Respostas
gabrielvb

A(8-2i)-(4+3i)= 8-4-2i-3i==> 4 - 5i  b) (6+10i)-(1-3i)= 6-1 +10i + 3i==> 5 + 13i  c) (5-2i).(1+3i) = 5+15i -2i -6i^2==>5+6 + 13i ==> 11 +13i

Adicionar resposta