Matematică
dumitrumonica86
6

1 calculati b) (2^8) ^2 : 2^2^4* (3^2-1)-3^0*2^2 c) (3^19 *25^9)^2:15^36

+0
(1) Răspunsuri
danielspoiala

b) (2^8) ^2 : 2^2^4* (3^2-1)-3^0*2^2= 2^16 : 2^8* (9-1)-1*2^2= 2^8* 8-2^2= 2^8 * 2^3* -2^2=2^11-2^3=2^3(2^6-1) c) (3^19 *25^9)^2:15^36=(3^19 *5^18)^2:(3*5)^36=(3^38 *5^36):(3^36*5^36)=3^2*5^0=9*1=9

Adaugă răspuns