Matematică
Leonetta
8

a)[latex] \frac{1}{4} x^{2} +3x+9= [/latex]=   [latex] x^{2} + \frac{2}{3}x+ \frac{1}{9} [/latex]=   [latex] \frac{1}{9} x^{2} - \frac{4}{3} x+4[/latex]=   [latex] x^{2} -x+ \frac{1}{4} [/latex]= b) [latex]3 x^{2} + 2\sqrt{6}x+2 [/latex]=    [latex]5+2 \sqrt{15}x+3 x^{2} [/latex]=    [latex]3-4 \sqrt{3}x+4 x^{2} [/latex]=    [latex]5 x^{2} -4 \sqrt{5}x+4 [/latex]=

+0
(1) Răspunsuri
laru

x²/4+3x+9=(x/2+3)² x²+2x/3+1/9=(x+1/3)² x²/9-4x/3+4=(x/3-2)² x²-x+1/4=(x-1/2)² 3x²+2√6x+2=(x√3+√2)² 5+2√15x+3x²=(√5+x√3)² 3-4√3x+4x²=(√3-2x)² 5x²-4√5x+4=(x√5-2)²

Adaugă răspuns