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Ce cantitate de dioxid de sulf(in grame,mol si litri) reazulta din arderea a 60 de grame sulf?

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S + O₂ = SO₂ M S = 32 g/mol M SO₂ = 32+16*2 = 32+32 = 64 g/mol 32/60 = 64/x x= 60*64/32 x= 3840/32 x= 120 g SO₂ 1 mol SO₂.... 64 g x moli SO₂..... 120 g 1/x = 64/120 x= 120/64 x= 1,875 moli SO₂ 1 mol SO₂ = 22,4 l 1,875 moli SO₂ = x l 1/1,875 = 22,4/x x= 1,875* 22,4 x= 42 l SO₂

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