Matematică
michelle999
6

cum se rezolva 2,5+[1,2+0,(6)]*3/7=? [1,(6)+2/3]*0,2+5/6=?

+0
(1) Răspunsuri
genius31

0,(6)=6/9=2/32,5+[1,2+0,(6)]x3/7=25/10+(12/10+2/3)x3/7= 25/10+(36/30+20/30)x3/7= 25/10+56/30x3/7= 25/10+8/10=33/10=3,3 1,(6)=(16-1)/9=15/9=5/3 [1,(6)+2/3]x0,2+5/6= (5/3+2/3)x2/10+5/6= 7/3x2/10+5/6= 14/30+5/6= 14/30+25/30=39/30=13/10=1,3

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