Matematică
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Perimetrul unui triunghi este egal cu 9 dm.Aflati lungimile laturilor triunghiului stiind ca ele sunt direct proportionale cu numerele 5,12,13. SOS

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GiulyGiulia

P=9 dm AB,AC,BC d.p 5,12,13 9 dm=9.10=90 cm AB=5K AC=12K BC=13K AB+AC+BC=90 cm 5k+12k+13k=90 30k=90 k=90:30 k=3 AB=5.k=5.3=15 cm Ac=12.k=12.3=36 cm BC=13.k=13.3=39 cm

memoreia

PERIMETRULtriunghi=AB+BC+AC=9DM [latex] \frac{AB}{5} [/latex]=[latex] \frac{BC}{12} [/latex]=[latex] \frac{AC}{13} [/latex]⇒[latex] \frac{AB+BC+AC}{5+12+13} [/latex]=[latex] \frac{PERIMETRU TRIUNGHI}{30} [/latex]=[latex] \frac{9}{30} [/latex] [latex] \frac{AB}{5}= \frac{9}{30} [/latex]⇒AB=[latex] \frac{45}{30} dm [/latex] [latex] \frac{BC}{12} [/latex]=[latex] \frac{9}{30} [/latex]⇒BC=[latex] \frac{108}{30} [/latex]dm [latex] \frac{AC}{13}= \frac{9}{30} [/latex]⇒AC=[latex] \frac{117}{30} dm[/latex]

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