Matematică
bogdanoiule
6

scrieti sub forma unei singure puteri cu exponent numar natural a)4 la puterea 16 *8 la puterea 12*16 la puterea 15 = b)25 la puterea 10 *5 la puterea 32 *125la puterea 5 = c)9 la puterea 4 *27 la puterea 5 *3 la puterea 14 d)a la puterea * b l\ puterea 2 *(a*b)la puterea 4*b la puterea 4

+0
(1) Răspunsuri
samysamuel12

a)4^16 *8^12*16^15 = (2^2)^16*(2^3)^12*(2^4)^15= 2^32*2^36*2^60 = 2^128 b)25^10 *5^32*125^ 5 = (5^2)^10*5^32*(5^3)^5= 5^20*5^32*5^15 = 5^67 c)9^4*27^5 *3^14=(3^2)^4*(3^3)^5*3^14= 3^8*3^15*3^14=3^37

Adaugă răspuns