Matematică
chiriaciucgeorgi
11

Stiind ca x+2y+13=24 , determinati 18+2y+x Stiind ca 3x+6y+19=43, determinati 6y+38+3x Stiind ca x +3+y+4+z+5 =12 determinati 2012+x+y+z

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x+2y+13=24  x+2y=24-13=11  18+2y+x=18+11=29 3x+6y+19=43  3(x+2y)+19=43  3(x+2y)=43-19=24  x+2y=24/3=8 6y+38+3x=3(x+2y)+38=3*8+38=24+38=62 x+3+y+4+z+5=12  x+y+z=12-3-4-5=0  2012+x+y+z=2012+0=2012

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